2x^2+xy=y^2-3y+2

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Solution for 2x^2+xy=y^2-3y+2 equation:


Simplifying
2x2 + xy = y2 + -3y + 2

Reorder the terms:
xy + 2x2 = y2 + -3y + 2

Reorder the terms:
xy + 2x2 = 2 + -3y + y2

Solving
xy + 2x2 = 2 + -3y + y2

Solving for variable 'x'.

Reorder the terms:
-2 + xy + 2x2 + 3y + -1y2 = 2 + -3y + y2 + -2 + 3y + -1y2

Reorder the terms:
-2 + xy + 2x2 + 3y + -1y2 = 2 + -2 + -3y + 3y + y2 + -1y2

Combine like terms: 2 + -2 = 0
-2 + xy + 2x2 + 3y + -1y2 = 0 + -3y + 3y + y2 + -1y2
-2 + xy + 2x2 + 3y + -1y2 = -3y + 3y + y2 + -1y2

Combine like terms: -3y + 3y = 0
-2 + xy + 2x2 + 3y + -1y2 = 0 + y2 + -1y2
-2 + xy + 2x2 + 3y + -1y2 = y2 + -1y2

Combine like terms: y2 + -1y2 = 0
-2 + xy + 2x2 + 3y + -1y2 = 0

The solution to this equation could not be determined.

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